SAP FIORI Interview Questions for freshers experienced | SAP Fiori Interview Questions | SAP FIORI Certification Dump 2022
126.What type of concurrency control is offered by OData?
ANS – Optimistic concurrency control
127.How does the OData Model handle XSRF tokens?
ans – The OData Model fetches the token when reading the metadata and sends the token automatically in each write
request header.
128.What is returned by the function createEntry?
ans – A binding context object.
129.When do you use deep insert?
ans – When working with hierarchical data where the data can only be stored in the full hierarchy.
130.What method must be implemented on the back end to support deep inserts?
ans – CREATE_DEEP_ENTITY
131.Which function do you call on the ODataModel to trigger a deep insert?
ans – create
132.What is the namespace in which the smart controls are bundled?
ans – sap.ui.comp
133.Which aggregation is used to overwrite the standard behavior of a SmartField control.
ans – configure
134.Which of the following statements are true for SAP Fiori elements?
a Heavy Ul coding is necessary when working with SAP Fiori Elements.
b SAP Fiori elements provide designs for Ul patterns and predefined templates.
c Apps are based on OData services and annotations.
Ans: B,C
135.Which of the following describe benefits of SAP Fiori elements?
A Consistent Ul design.
B Full control of the of the generated code at design time.
C Less support effort.
D Flexibility and freedom in Ul design.
Ans: A,C
136.Which of the following SAP Fiori element based Uls are currently available?
A Wizard Form
B List Report
C Master- Detail
D Overview Pages
E Object Page
Ans: B,D,E
137.Which Ul annotation is used in the object page to display the object header?
ANS – Ul.headerlnfo
138.Which Ul annotation is used to declare a field for the smart filter template?
ans – UlselectionField
139.What is meant by the phrase “SAPUI5 supports modification free enhancements”?
ANS – he delivered standard application remains unchanged and hence the extension is considered to be modification free.
140.Is it possible to add an extension point in the component implementation?
ANS – NO
141.To what namespace is the ExtensionPoint class assigned?
ans – sap.ui.core
142.What types of extensions/replacements are supported by SAPUI5?
A Component replacement
B View replacement
C View modification
D Replace service
E Implement Ul Controller Hooks
F Manifest.json replacement
Ans: B,C,D
143.When you implement a controller extension and you implement the onlnit and onAfter Rendering functions in the extension, when are
they called?
ANS – After the corresponding functions form the standard controller.
144.How is the extension type called to hide UI controls?
ANS – View modification
145.Which of the following best describes a commit?
ANS – With every commit. GIT takes a snapshot of the current state of the underlying files.
146.Which of the following are the main states of a file in GIT?
A Committed
B Changed
C Released
D Modified
Ans: A,B,D
147.In which state are the files in GIT when a remote repository is cloned?
A Staged and modified
B Tracked and unmodified
C Tracked and staged
D Modified and tracked
Ans: A,B,D
148.What is the result of a GIT Reset?
ANS – Returns a project back to the previous state.
149.What is the result of a GIT Revert?
ANS – Undoes a committed snapshot.
150.What is the result of a GIT Clean?
ANS – Removes all untracked files from the working directory.
151.Choose the correct answer What is a GIT branch?
ans – A GIT branch represents an independent line of development.
152.Which of the following statements are true about the merge functionality in GIT?
ANS – Allows integration of a branch into another branch.
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